a room is of 11m×8m×5m.Find the cost of cementing its four wall and floor at the rate of ₹4 per square metre including door and windows.
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Answered by
139
given that
l = 11 m
b = 8 m
h = 5 m
top of the room = lb
= 11 × 8
= 88 m
TSA of the cuboid = 2(lb + bh + hl)
=2(11×8 +8×5 + 5×11)
=2(183)
= 366 m²
what we want the by question = 366 - 88
= 278 m
floor at the rate of the rs.4 = 278 × 4
=1112 rupees
l = 11 m
b = 8 m
h = 5 m
top of the room = lb
= 11 × 8
= 88 m
TSA of the cuboid = 2(lb + bh + hl)
=2(11×8 +8×5 + 5×11)
=2(183)
= 366 m²
what we want the by question = 366 - 88
= 278 m
floor at the rate of the rs.4 = 278 × 4
=1112 rupees
Answered by
8
Answer:
1112₹
Step-by-step explanation:
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