Question

A room is of 11m x 8m x 5m. find the cost four wall and floor at rate of 4 per square
metre​

Answer 1

Step-by-step explanation:

Area of 4 walls of the room = 2(l+b)h

Area of 4 walls of the room = 2(l+b)h=2h(l+b)

Area of 4 walls of the room = 2(l+b)h=2h(l+b)= 2*5(11+8)

Area of 4 walls of the room = 2(l+b)h=2h(l+b)= 2*5(11+8)= 10(19)

Area of 4 walls of the room = 2(l+b)h=2h(l+b)= 2*5(11+8)= 10(19)= 190m2

Area of 4 walls of the room = 2(l+b)h=2h(l+b)= 2*5(11+8)= 10(19)= 190m2Rate of cementing = Rs.4/m2

Area of 4 walls of the room = 2(l+b)h=2h(l+b)= 2*5(11+8)= 10(19)= 190m2Rate of cementing = Rs.4/m2Cost of cementing the four walls of the room = 4*190

Area of 4 walls of the room = 2(l+b)h=2h(l+b)= 2*5(11+8)= 10(19)= 190m2Rate of cementing = Rs.4/m2Cost of cementing the four walls of the room = 4*190= Rs.760

Area of 4 walls of the room = 2(l+b)h=2h(l+b)= 2*5(11+8)= 10(19)= 190m2Rate of cementing = Rs.4/m2Cost of cementing the four walls of the room = 4*190= Rs.760Hence the cost of cementing the four walls is Rs. 760

Answer 2

Answer:

440

Step-by-step explanation:

first we calculate the multiplication first we multiply 11 is multiplied by 8 multiplied by 5 we get the answer of 440