Math, asked by sristi92, 1 year ago

A room measure 12 m × 9 m . the floor of the room is to be covered by marbel tiles measuring 45cm by 30 cm . how many tiles are needed​

Answers

Answered by bittu3645
2

length of room=12m

breadth of room=9m__given

area of floor=12m×9m

=108m^

=1080000cm^

again,

measure of tile=45cm by 30 cm

area of a tile=45cm×30cm

=1350cm^

no. of tiles needed=1080000cm^/1350cm^

=800 tiles.


bittu3645: are u active
Answered by ItzSanam126
1

\huge\mathbb\pink{Solution- }

Given that,

Length of room = 12 m

Breadth of room = 9 m

So area of the room= length × breadth

=(12 × 9) m^2

= 108 m^2

= 1080000 cm^2

Also given that,

Area of tiles = (45 × 30) cm ^2

  • =1350 cm^2

Number of tiles required =1080000/1350

  • = 800 tiles.

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