Question

A room measurements are 6 mts length. 5 mts width and 4 mts height. The room does not have doors or windows.
Find out the total area of walls of that room.
(A) 20 sq. mts.
(B) 24 sq. mts.
(C) 120 sq. mts.
(D) 88 sq. mts​

Answer 1

ANSWER:

d) 88 m²

STEP-BY-STEP EXPLANATION:

Given that a room measurements are 6 mts length. 5 mts width and 4 mts height. The room does not have doors or windows.

We need to find out the total area of the room.

Let's say the total area of the room is x.

Now,

Total area of the walls of the room = 2(lh + bh)

(Where length is 6 m, breadth or width is 5 m and height is 4 m)

Substitute the values,

→ x = 2(6*4 + 5*4)

→ x = 2 × 4(6 + 5)

→ x = 8(6 + 5)

→ x = 8(11)

→ x = 88

Therefore, the total area of walls of the room is 88 m².

Answer 2

Following are the steps for getting the answer:

Given:

a room's measurements are 6 mts in length.

5 mts width and 4 mts height.

The room does not have doors or windows.

 to find :

the total area of the room.

Solution:

Let's say the total area of the room is x.

Now,

the Total area of the walls of the room = 2(lh + bh)

(Where length is 6 m, breadth or width is 5 m and height is 4 m)

Substitute the values,

 x = 2(6*4 + 5*4)

 x = 2 × 4(6 + 5)

x = 8(6 + 5)

x = 8(11)

x = 88

Therefore, the total area of walls of the room is 88 m².