Question

A room measures 25 m x 18 m x 15 m. Find the maximum number of bricks each measuring 2 m x 5 m x 3 m that can be kept in a room

plz answer​

Answer 1

Answer:

225 bricks needed to kept a room

Answer 2

★GIVEN★

• A room measures 25 m x 18 m x 15 m.
• Bricks each measuring 2 m x 5 m x 3 m.

★To Find★

Maximum number of bricks that can be kept in a room.

★SOLUTION★

Total Surface area,

$\large{\green{\underline{\boxed{\bf{Surface\:Area=Length\times\:Breadth\times\:Height}}}}}$

So,

Total Surface Area of Room,

$\large\implies{\sf{Surface\:Area=Length\times\:Breadth\times\:Height}}$

$\large\implies{\sf{Surface\:Area=25\times18\times15}}$

$\large\therefore\boxed{\bf{Surface\:Area\:of\:room=6,750\:{m}^{3}.}}$

Now,

Total Surface Area of Bricks,

$\large\implies{\sf{Surface\:Area=Length\times\:Breadth\times\:Height}}$

$\large\implies{\sf{Surface\:Area=2\times5\times3}}$

$\large\therefore\boxed{\bf{Surface\:Area\:of\:bricks=30\:{m}^{3}.}}$

Now maximum no of bricks,

$\large{\green{\underline{\boxed{\bf{No\:of\:bricks=\dfrac{Surface\:area\:of\:room}{Surface\:area\:of\:bricks}}}}}}$

$\large\implies{\sf{No\:of\:bricks=\dfrac{6750}{30}}}$

$\large\implies{\sf{No\:of\:bricks=\dfrac{\cancel{6750}}{\cancel{30}}}}$

$\large\therefore\boxed{\bf{No\:of\:bricks=225.}}$

Maximum number of bricks that can be kept in the room is 225.