A room measuring 7 m by 6m is to be covered by square tiles of side 21cm.Find the number of tiles required to cover the floor.If the cost of one tile is ru.40,find the total cost of tiles?
Answers
Answer:
- The total cost of tiles is Rs 38080.
Step-by-step explanation:
Given that:
Dimensions of a room.
- Length = 7 m
- Breadth = 6 m
The floor of room is covered with square tiles.
- Side of square tiles = 21 cm
- The cost of one tile = Rs 40
To Find:
- The total cost of tiles.
First converting the dimensions of room in cm:
We know that.
1 m = 100 cm
Length = 7 m = (7 × 100) = 700 cm
Breadth = 6 cm = (6 × 100) = 600 cm
Formula used:
- Area of rectangle = (Length × Breadth)
- Area of square = (side × side)
- Number of tiles = (Area of floor of room)/(Area of each square tile)
Finding the number of tiles:
⟶ Number of tiles = (700 × 600)/(21 × 21)
⟶ Number of tiles = 420000/441
⟶ Number of tiles ≈ 952
∴ The number of tiles = 952
Finding the total cost of tiles:
⟶ Cost of one tile = Rs 40
⟶ Cost of 952 tiles = Rs (40 × 952)
⟶ Cost of 952 tiles = Rs 38080
∴ The total cost of tiles = Rs 38080
Answer:
Given :-
A room measuring 7 m by 6m is to be covered by square tiles of side 21cm.
To Find :-
number of tiles required to cover the floor.If the cost of one tile is ru.40,find the total cost of tiles?
Solution :-
7 m = 700 cm
6 m = 600 cm
Area of room = l × b
=> 700 × 600
=> 420000 cm²
Area of tile = side²
=> (21)²
=> 441 cm²
No. of tiles = 420000/441
No. of tiles = 952
Cost = No. of tiles × Rate
Cost = 952 × 40
Cost = 38080
Step-by-step explanation: