Question

A room measuring 7 m by 6m is to be covered by square tiles of side 21cm.Find the number of tiles required to cover the floor.If the cost of one tile is ru.40,find the total cost of tiles?​

Answer 1

Answer:

Answer:

. The total cost of tiles is Rs 38080.

Step-by-step explanation:

Given that:

Dimensions of a room.

. Length = 7 m

Breadth = 6 m

The floor of room is covered with square tiles.

Side of square tiles = 21 cm

The cost of one tile = Rs 40

To Find:

The total cost of tiles.

First converting the dimensions of room

in cm:

We know that.

1 m = 100 cm

Length = 7 m = (7 x 100) = 700 cm

Breadth = 6 cm = (6 x 100) = 600 cmFormula used:

Area of rectangle = (Length Breadth) Х

. Area of square = (side x side) Number of tiles = (Area of floor of

room)/(Area of each square tile)

Finding the number of tiles:

>

Number of tiles = (700 x 600)/(21 ×

Number of tiles = 420000/441

Number of tiles = 952

21)

.. The number of tiles = 952 =

Finding the total cost of tiles:

Cost of one tile = Rs 40

Cost of 952 tiles = Rs (40 x 952)

Cost of 952 tiles = Rs 38080

Answer 2

$\huge \huge \bf {\: \pmb{Question}}$

Q. A room measuring 7 m by 6m is to be covered by square tiles of side 21cm. Find the number of tiles required to cover the floor.If the cost of one tile is ₹40 , find the total cost of tiles?

$\star\bf{\:\pmb{Given}}$

• there's a room that measures 7m and 6m

• room's square tile that measures 21cm

• charges of one tile is ₹40

$\bf {\: \pmb{Required~to~find}}$

• cost of total tiles

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$\huge \huge \bf {\: \pmb{Solution}}$

➳ 1:

• Area of room

as given , length and breadth of room is 7m and 6m.

so, 700cm as length and 600cm as breath.

• Area of room = length × breath

= 700cm × 600cm

= 420000cm²

• area of room is 420000cm²

➳ 2:

• Number of tiles required to cover the room

as given , side of a square tile is 21cm so area will be :-

• Area of square tile = side²

= (21cm)²

= 441cm²

• area of 1 tile is 441cm²

now leading to the main thing,

number of tiles = $\frac{Area ~of~ room}{Area~of~1~tile}$

= $\frac{₹420000}{441}$

= 952 tiles

• therefore , 952 is required to cover the room

➳ 3

• total cost of the total tile used

as given , 1 tile costs ₹40

so , for 952 tiles

= ₹40 × 952tiles

= ₹38080

thus, total cost of 952 tiles is ₹38080

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