A room of dimension 18m*10m*5m is to be painted. if each can of paint covers 90m2 of area then how cans are required to paint the room.
TB49THEGHOST:
Is the shape of the room given?
yes
Answers
Answered by
4
Area of room = 18m×10m×5m
= 900 m^2
if each can of paint covers 90m2 of area
SO,
Required cans for painting = 900/90
= 10
this is your answer.....
I hope it will help you.....
= 900 m^2
if each can of paint covers 90m2 of area
SO,
Required cans for painting = 900/90
= 10
this is your answer.....
I hope it will help you.....
Hey afsana this answer is totally wrong because this person has taken out volume instead of area
ohh sorry i missed it....
sorry
Answered by
1
Total surface area of room =2(lb+bh+lh)
=2(180+50+90)
=2*320
=640m2
No of cans required =640\90
=64\9 cans
This questions answer will come in fraction.
Hope this answer helps you
=2(180+50+90)
=2*320
=640m2
No of cans required =640\90
=64\9 cans
This questions answer will come in fraction.
Hope this answer helps you
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