Math, asked by vivekverma174, 1 year ago

a room whose dimensions are 7m by 5m by 4m has a door 2.5m by 1m and two square windows of length 1m each. find the area of the wall to be painted. exculeding door and windows

Answers

Answered by Anonymous

Area of walls = 2(12)4
=48×2
=96m²
So, required area = 96-4.5
=91.5m²

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vivekverma174: to sahi ans de

Anonymous: given

Anonymous: Ye toh Thik hoga??

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Anonymous: us pic k neeche

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Anonymous: all right

vivekverma174: the circumfrence of the base of a cylinder is 132 cm. find the volume of the cylinder is its hight is 10/3 cm.

vivekverma174: plz send me ans na

Anonymous: sorry one more is answering I can't answer it right now

Answered by 9652702375

First take LSA of the room.
That is, 2(lb+bh)
=2 (7×5+5×4)
=2 (35+20)
=2 (55)
=110m^2
Now take the area of door and Windows.
Door=l×b
=2.5×1
=2.5m^2
Windows=2 (l×b)
=2 (1×1)
=2m^2
Area of the wall to be painted = 110-2.5-2
=105.5m^2

Anonymous: O hello breadth is 4cm not 5

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