Question

a root of 2x^2-5x+k=0 is 2 then then the other find k​

Answer 1

given quadratic polynomial is p(X)=2x^2-5x+k=0

from given 2 is a root of this polynomial

so if we substitute 2 in place of X then

p(2)=0

2(2)^2-5(2)+k=0

8-10+k=0

-2+k=0

k=2

hence the Value of k is 2