Question

a roots of equation (x-1) (x-2) =30/49​

Answer 1

Answer:

Hi your answer is as follows

Step-by-step explanation:

on multiplying we get,

(x-1)(x-2) = $\frac{30}{49}$

$x^2-2x-x+2=\frac{30}{49} \\\\x^2-3x+2=\frac{30}{49} \\\\Cross~multiplying;\\\\49x^2-147x+98=30\\\\49x^2-147x+68=0$

using Sridharacharya's formula we get roots as;

$\frac{-147+-\sqrt{21609-13328}}{98} \\\\\frac{-147+-\sqrt{8281}}{98} \\\\\frac{-147+-91}{98}\\\\Roots~are:\\\\\frac{-56}{98}~and~\frac{-238}{98}\\\\On~simplification ~we ~get\frac{-4}{7}~and~\frac{-17}{7}$

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