Math, asked by morampudinani766, 16 days ago

a rope 1.98cm long was cut into parts so that 1 part turned out to be 20% longer than the other part then the lengths​

Answers

Answered by vrickshik
0

Answer:

Shorter part : 0.9 cm and Longer part : 1.08 cm

One rope be X

Other rope will be x * 120% = 1.2x

1.2x + x =1.98

2.2x = 1.98

x = 1.98/2.2

x = 0.8cm

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Answered by chandujnv002
0

Answer:

the two parts of the rope have lengths of 0.9 cm and 1.08 cm, respectively.

Step-by-step explanation:

Let's call the length of one part of the rope "x".

According to the problem, the other part of the rope is 20% longer than "x". We can find the length of this part by multiplying "x" by 1.2 (which is 100% + 20% = 120% or 1.2 as a decimal):

Length of longer part = 1.2x

We know that the total length of the rope is 1.98 cm,

so we can set up an equation to represent this:

x + 1.2x = 1.98

Simplifying the equation:

2.2x = 1.98

x = 0.9

So one part of the rope is 0.9 cm long.

To find the length of the other part of the rope, we can use the equation we set up earlier:

Length of longer part = 1.2x

Length of longer part = 1.2(0.9)

Length of longer part = 1.08

So the other part of the rope is 1.08 cm long.

Therefore, the two parts of the rope have lengths of 0.9 cm and 1.08 cm, respectively.

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