Math, asked by shaikshabana3663, 1 month ago

A rope,36 1/3m,long was cut into 3parts mesuring 12 2/5,13 1/2m,and 5 4/15 tespectly what was the length of the rope left

Answers

Answered by jeevashankar2

2

Answer:

109/3= 62/5+27/2+79/15+x

1090/30=(372+405+158+30x)/30

1090=372+405+158+30x

30x= 155

x= 5 1/6

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