Question

a rope by which a calf is increased from 12m to 23m . how much additional grassy ground shall it graze ?

Answer 1

Answer:

Step-by-step explanation:

original area cow is grazing=(area of whole circle of radius 12 m)= pie*r^2=pie*144=144*pie sq. m

new area cow is grazing=(area of circle of radius 23 m)=pie*R^2=pie*529=529*pie sq. m

increased area=(529*pie-144*pie)sq. m=(529–144)*pie sq. m

=385*pie sq.m=1210 sq. m

Answer 2

original area calf is gazing =( area of whole circle of native 12 m)

$\pi \: r ^{2} = \pi \times 12 \times 12 \\ = 144\pi \: m ^{2}$

new area calf is gazing

=( area of circle of native 23 m)

=

$\pi \: r ^{2} = \pi \times 23 \times 23 \\ = 529\pi \: m^{2}$

increased area is =

$= 529\pi \: m ^{2} - 144\pi \: m ^{2}$

$= 385\pi \: m ^{2} = 385 \times \frac{22}{7} m^{2} \\ = 1210m ^{2} ans$

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