Question

a rope dancerwas walking on a loose ropes tired to the tops of twopoints each 10m high. when a dancer was 2m abovetheground it was found that the stretched pieces of the rope sub tended the angle 30 and 60 with the horizontal lines parallel to the ground. find the length of rope​

Answer 1

hope it helps you

please mark my answer as brilliant

Step-by-step explanation:

This one would require you to draw a diagram to understand the solution.

Two triangles will be formed. Each of them will have the hypotenuse as the rope, a second side (height) as one of the two posts, and a third imaginary side as the base.

Both lengths along the post are 6m (9m-3m)

Now, you can find the lengths of the two stretched pieces of rope using the given angles and the 6m side:

Hypotenuse = Height / sinθ

a) First piece = height / sin30

= 6 / (1/2)

= 12 m

b) Second piece = height / sin60

= 6 / (√3/2)

= 12/√3m

= 4√3 m

Total length = 12 + 4√3 m