Math, asked by ajijikbalansari, 1 month ago

A rope is 20m long. If 40% of it is cut and taken away. how much of it is left ​

Answers

Answered by anubhabkumar2020
0

Answer:

Step-by-step explanation:

Length of the rope =40cm let length of the piece =x

a. Length of the other piece =40−x

b. Length of the sides of the square

=

4

x

and

4

40−x

c. The algebraic form, Given, sum of the area 58cm

2

.

ie., a

2

+a

2

=58cm

2

.

⇒(

4

x

)

2

+(

4

40−x

)

2

=58

16

x

2

+

16

1600−80x+x

2

=58

⇒2x

2

−80x+1600=58×16

1x

2

−80x+1600=928

dividing through out by 2,

ie., x

2

−40x+800=464.

⇒x

2

−40x+800−464=0

⇒x

2

−40x+800−464=0

⇒x

2

−40x+336=0

Length of each piece,

x

2

−40×336=0 (factorize)

⇒(x−28)(x−12)=0

⇒x−28=0 or x−12=0

x=28 or x=12

The length of each pieces =28m or 12m.

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