Physics, asked by muskaankurdia54, 6 hours ago

a rope is being pulled from both ends. Each man and woman pull the rope with 30N and 20N force respectively. if there are 4 men and 3 women pulling the rope from one end then how many men and women will be there on the other end when the tension in the rope is zero

Answers

Answered by abbasalimullickclass
1

Answer:

30÷20 =3/2 = 1.5 3men 2women

Answered by GulabLachman
2

Given: A man and woman pull the rope with 30 N and 20 N force respectively. There are 4 men and 3 women on one end.

To find: Number of men and women on other side when tension in rope is zero.

Explanation: For tension to be zero in the rope, the force applied on both sides should be equal so that the force applied cancels each other and no net tension remains on the rope.

Now, Force by 1 man = 30 N

Therefore, force by 4 men = 4*30 = 120 N

Force by 1 woman= 20 N

Therefore, force by 3 women= 3*20 = 60 N

Total force on one side= 120+60= 180 N

Now, we need to divide 180 N into number of women and men. If there are 2 men and 6 women on other side, then force by 2 men = 60 N and force by 6 women = 120 N. It therefore amounts to 180 N.

Any other combination would not result in exactly 180 N. It would either be greater or lesser than 180 N.

Therefore, 2 men and 6 women on other side would perfectly balance 4 men and 3 women and the tension in the rope is zero.

Similar questions