Question

A rope is connected between two points a and b 120 cm apart at the same level. A load of 200 n is suspended from a point c on the rope 45 cm from a as shown in fig. 5.10. Find the load, that should be suspended from the rope d 30 cm from b, which will keep the rope cd horizontal. Solution

Answer 1

Answer:100N

Explanation:

In this question we have to consider equilibrium of moments on these two points about a And b.

First considering the moment in the point about C.

This moment Ma will be = load* distance from C to A = 200*45=9000

To maintain equilibrium the moments of Load at C and D will be same about point B

Now moment of load But about point C will be

Mb = load*distance from point A to D

9000= load*(120-30)

Load at D = 9000/90= 100N