Question

a rope is cut into three peaces in ratio 1:3:5.given that the length of the longest piece is 35m find @ the length of origional rope and the length of the shortest piece of rope​

Answer 1

Answer:

63 m & 7 m

Step-by-step explanation:

As the ratio is 1:3;5, let the length of ropes be a, 3a and 5a.

Longest part = 5a. But in question it is 35 m.

=> 5a = 35 m → a = 7 m

Hence,

a. Total length = a + 3a + 5a

= 9a = 9(7m)

= 63 m

b. Shortest part = a = 7 m

Answer 2

$given \\ \\ ratio \: \: \: of \: \: \: rope \: \: \: cut \: \: \: 1.3.5 \\ \\ longest \: \: \: length = 35cm \\ \\ \: to \: \: \: find = (1)original \: length \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2)shortest \: \: \: \: length \\ \\ solution = \\ \\ let \: \: x \: \: be \: \: the \: \: \: multiple \: \: \: of \: \: \: ratios \\ \\ \\ \\ hence \: \: \: x.3x.5x \: \: \: new \: \: \: ratios \\ \\ 5x = 35 \: \: \: \: \: \: \: \: \: \: ....(given \: \: large \: \: piece) \\ \\ 5x = 35 \\ \\ x = 7 \\ \\ hence \\ \\ x + 3x + 5x = 9x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 9 \times 7 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= 63 \\ \\ short \: \: \: piece \: \: = \: 7cm \\ \\ \\ \\ \\ please\: \: \: mark \: \: \: me \: \: as \: \: \: brainlist \: \: \:$