Question

a rope is lies on a table such that a part of it hangs down the table,when the length of hanging part is 1/3 of entire length the rope just begins to slide.the coefficient between the rope and the table is

Answer 1

The question is incomplete.

However,

Given:

Length of hanging rope = (1/3) of entire length the rope

Mass of hanging rope = (1/3) of the length of the rope * mass of the rope

Length of the rope on the table = (2/3) Length of hanging rope

Mass of the rope on the table = (2/3) Length of hanging rope * mass of the rope

To find:

The coefficient of friction between the rope and table.

Solution:

Consider,

x as the coefficient of friction

By law,

The weight of rope on the table = The weight of hanging rope

x * (2/3) Length of hanging rope × mass of the rope * gravity  = (1/3)  Length of hanging rope × mass of the rope * gravity

x = 1/2

We get,

x = 0.5

Hence, the required coefficient of friction between the rope and table is 0.5.