Question

A rope of length 10m and linear density 0.5kg/m is lying length wise on a smooth horizontal floor. It is pulled by a force of 25 N. The tension in the rope at a point 6m away from the point of application is
1)20 N

2)15 N

3)10 N

4)5 N
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Answer 1

Solution :

Given,

Mass of rope (m) = 10 × 0.5 = 5 kg

Force (F) = 25 N

We know that,

$\implies$ $\boxed{\sf{a=\frac{F}{m}}}$

By substituting the values, we get:

$\implies$ a = 25/5

$\implies$ a = 5 m/s²

Mass of rope remaining after 6 m:

$\implies$ 4 m × 0.5 kg/m

$\implies$ 2 kg

Tension at point 6 m from point of application:

$\implies$ 2 kg × 5 m/s²

$\implies$ 10 N

Hence, tension at that point is 10 N.

Therefore:

Correct option: (3) 10 N

_________________

Answered by: Niki Swar, Goa❤️

Answer 2

A rope of length 10m and linear density 0.5kg/m is lying length wise on a smooth horizontal floor. It is pulled by a force of 25 N. The tension in the rope at a point 6m away from the point of application is

1)20 N

2)15 N

3)10 N ✔️

4)5 N