Question

A rope of length 10m and linear density 0.5kg /m is lying length wise on a smooth horizontal floor. It is pulled by a force of 25N. the tension in the rope at a point 6m away from the point of application is?

Answer 1

mass of rope = 10×0.5 = 5kg
Force = 25N
a = F/m = 25/5 = 5 m/s2

mass of rope remaining after 6m = 4m × 0.5 kg/m = 2kg
a = 5 m/s2
Tension at point 6m from point of application= 2kg × 5 m/s2 = 10N

Tension at that point is 10N

Answer 2

Answer:

C

Explanation:

Force on unit length =FL,

Force on l units of length =(FL)l

Tension at (L−l) length =FL(L−l) .