A rope of length 10m and linear density 0.5kg/
m is lying length wise on a smooth horizontal
floor. It is pulled by a force of 25 N. The tension
in the rope at a point 6m away from the point of
application is
A) 20 N
B) 15 N
C) 10 N
D) 5N
Answers
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Length slope =10m
Density =0.5kg/m
Given the floor is smooth
T=25N
(Ref image)
FBDs of the two parts
Let total mars of rope be m.
The left part has a mars 0.6m and right part
mars 0.4m as rope is uniform.
The rope moves as a single piece.
So acceleration of both parts have to be same
T−T
1
=(0.6m) a from (1)
T
1
=0.4ma from (2) of ma=
0.4
T
T−T
1
=0.6×T
1
0.4
T=2.5T
1
T
1
=2T
5
Putting T=25N
T
1
=10N
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