a rope of length 15m is suspended from a tree. a man of mass 50kg climbs along the rope in vertical direction witha constant acceleration g/3. Find the work done by the rope on the man. (g= 10m/s²)
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Answer:
2500 J
Explanation:
W = mgh
= 50 × 10/3 × 15 (g = 10 )
= 2500 J
= 2.5 kJ
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