A rope of length 5m is kept on a metionless surface and a foree 10applied te one end of the rope in the direction of its length away from that and then the ratio of Tension at a distance 2m to the applied force.
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Answer:
Length of the ropeL =5m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope=
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a=
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF =
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5 Mass of the 4 m long rope that tension pullsM=
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5 Mass of the 4 m long rope that tension pullsM= 5
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5 Mass of the 4 m long rope that tension pullsM= 54m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5 Mass of the 4 m long rope that tension pullsM= 54m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5 Mass of the 4 m long rope that tension pullsM= 54m
Length of the ropeL =5mLet m be the mass of the rope. Mass per unit length of the rope= 5m Acceleration of the rope a= mF = m5 Mass of the 4 m long rope that tension pullsM= 54m .