Question

a rope of mass 0.5 kg is pulling a block of mass 10 kg under the action force of 31.5 N . if the block is resting on a smooth horizontal surface calculate the force of reaction exerted by the block on the rope

Answer 1

The force of reaction exerted by the block on the rope is 30 N

Explanation:

• First we need to calculate the force that is being exerted on the block

• Total mass = 0.5 + 10 = 10.5 kg

• Force = ma that give a = F/m

• Acceleration = 31.5/10.5 = 3 m/s2

• Now, we can calculate the force of reaction by block on the rope using this value of acceleration

• F= ma = 10 *3 = 30 N