Question

a rope of mass 2 kg and length one metre is pulled along the smooth horizontal Floor by the central force of 40 Newton as shown what is the tension at point p (g =10 m/s² and string and Pulley is light and frictionless) (1)32N (2)26N (3)18N (4) 49N ​

Answer 1

Answer: 26 N

Explanation:

Answer 2

Concept: Force is an external agent that has the power to alter a body's resting or moving position. It has a direction and a magnitude. The direction of the force is referred to as the force's direction, and the point of application is where the force is exerted. A spring balance can be used to calculate the Force. Newton is the SI unit of force (N).

Given: Mass of rope = 2kg

           Length of rope = 1m

           Central force = 40N

           g = $10 m/s^{2}$

           string and pulley is light and frictionless

To find: The tension at  point P

Solution: Refer the figure for clear explanation,

On whole system,

40 - 1 × g = (1 + 2)a

40 - 1 × 10 = 3a

40 - 10 = 3a

30 = 3a

$\frac{30}{3}$ = a

a = $10m/s^2$

Now for part P,

mass of part P portion = $\frac{70}{100} * 2$

                                     = 1.4 kg

Therefore,

$T_{p} = 40 - 1.4*a\\T_{p} = 40 - 1.4*10\\T_{p} = 40 -14\\T_{p} = 26 N$

Hence, tension at point P is 26N.

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