Question

A rope of mass 5kg is moving vertically in vertical position with an upward force of hundred Newton acting at the upper end and a downward force of 70 Newton acting at the lower end. The tension at midpoint of the rope is

Answer 1

Answer:

85 N

Explanation:

Applying newtons law of motion, we have

100−(70+5×g)=5×a

acceleration is given by,100−70−50=5×a

a=−4m/s

2

in the downward direction.

Let the tension be T, mass of the half rope will be 2.5 kg,

Substituting this value in the Newton's IInd law of motion gives us

70+2.5g−T=2.5×4

T=85 newton