A rope of negligible mass is wound around a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceleration of the cylinder, if the rope is pulled with a force of 30 N? What is the linear acceleration of the rope? Assume that there is no slipping.
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Answered by
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Hii friend,
● Answer-
a) α = 25 rad/s^2
b) p = 10 m/s^2
● Explaination-
# Given-
m = 3 kg
r = 40 cm = 0.4 m
F = 30 N
# Solution-
a) Angular acceleration -
α = τ/I
α = (Fr)/(mr^2)
α = F/(mr)
α = 30/(3×0.4)
α = 25 rad/s^2
b) Linear acceleration-
p = rα
p = 0.4×25
p = 10 m/s^2
Hope that helps you...
● Answer-
a) α = 25 rad/s^2
b) p = 10 m/s^2
● Explaination-
# Given-
m = 3 kg
r = 40 cm = 0.4 m
F = 30 N
# Solution-
a) Angular acceleration -
α = τ/I
α = (Fr)/(mr^2)
α = F/(mr)
α = 30/(3×0.4)
α = 25 rad/s^2
b) Linear acceleration-
p = rα
p = 0.4×25
p = 10 m/s^2
Hope that helps you...
Answered by
1
Answer:
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