Question

A rope, under a tension of 323 n and fixed at both ends, oscillates in a second-harmonic standing wave pattern. The displacement of the rope is given by y=(0.207 m)sin(x/4.00)sin(11.0t). Where x=0 at one end of the rope, x is in meters, and t is in seconds. What are (a) the length of the rope, (b) the speed of the waves on the rope, and (c) the mass of the rope? (d) if the rope oscillates in a third-harmonic standing wave pattern, what will be the period of oscillation?

Answer 1

Answer:

(b) and (c)

Explanation:

if the rope oscillates in a third- harmonic standing wave pattern,a rope under a tension of 323.