a round ballon of radical &
substend an angle of at the eyes of
observer while the angle of elevation of the
centre ( balloon) is ßProve that the
height of the centre of the ballon
r. Sinß .cos alpha by 2
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Answer:
Let O be the centre of the balloon and P be the eye of the observer
And ∠APB be the angle subtended by the balloon
∴∠APB=α
∴∠APO=∠BPO=
2
α
In △OAP,sin
2
α
=
OP
OA
⟹sin
2
α
=
OP
r
⟹OP=r cosec
2
α
−(1)
In △OPC
sinβ=
OP
OL
or OL=OPsinβ
∴OL=r cosec
2
α
sinβ
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