Question

A round face clock in Roman block numbers fell down and the dial broke into 4 parts . The numerals in each part in every case some to a table of 20 . Can you show how the four parts of the clock face was broken?​

Answer 1

Two Ways Shown how the Roman Block numbers clock broken in 4 Equal parts of 20  

Step-by-step explanation:

Clock has numbers 1 to 12

which adds up

12 * 13/2 = 78

Each Part is broken in sum of 20

there are four parts

=> 20  * 4 = 80

There is additional sum of 2  

which can be in two cases

case 1  :

IV   is divided

then it becomes  I + V  

=> 4 becomes 6

| (from XI) + XII  + I  + II  + III + I (from IV broken) = 20

X + X  ( X from XI)  = 20

VIII + VII  + V ( V from VI) = 20

IX + V ( from IV) + V  + I  ( from VI) = 20

Case 2 :

IX  is divided

then it become  I + X

=> 9 becomes 11

X (from IX) + X = 20

XI + VIII + I  ( from IX) = 20

XII + VII + I  = 20

II + III + IV  + V  + VI = 20

Solution attached as well

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