Math, asked by prince02012006, 8 months ago

a round table cover has six equal design as shown in figure 12.14 if the radius of the cover is 28 cm find the cost of making the design at the rate of rupees 0.35% square use root 3 equal to 1.7??

Answers

Answered by Unni007
6

Answer:

Total cost of making design = Rs 162.66 rupees

Step-by-step explanation:

Given,

  • Number of equal designs = 6
  • Radius of round table cover = 28 cm
  • Cost of making design = Rs  0.5 per cm²
  • ∠O = 360°/6 = 60°

ΔAOB is isosceles as two sides are equal (Radius of the circle)

∴ ∠A = ∠B

Sum of all angles of triangle = 180°

∠A + ∠B + ∠O = 180°

⇒ 2 ∠A = 180° - 60°

⇒ ∠A = 120°/2

∠A = 60°

Triangle is equilateral as ∠A = ∠B = ∠C = 60°

Area of equilateral ΔAOB = √3/4 × (OA)² = √3/4 × 282 = 333.2 cm²

Area of sector ACB = (60°/360°) × π r² cm²

                                 = 1/6 × 22/7 × 28 × 28 = 410.66 cm²

Area of design = Area of sector ACB - Area of equilateral ΔAOB

                          = 410.66 cm² - 333.2 cm² = 77.46 cm²

Area of 6 design = 6 × 77.46 cm² = 464.76 cm²

Total cost of making design = 464.76 cm² × ₹ 0.35 per cm² = Rs 162.66

∴ Total cost of making design = Rs 162.66 rupees

Answered by VaibhaVShinde00
4

Answer:

Step-by-step explanation:

Answer:

Good  night

Step-by-step explanation:

Sum of all angles of triangle = 180°

∠A + ∠B + ∠O = 180°

⇒ 2 ∠A = 180° - 60°

⇒ ∠A = 120°/2

⇒ ∠A = 60°

Triangle is equilateral as ∠A = ∠B = ∠C = 60°

Area of equilateral ΔAOB = √3/4 × (OA)2 = √3/4 × 282 = 333.2 cm2

Area of sector ACB = (60°/360°) × π r2 cm2

                                           = 1/6 × 22/7 × 28 × 28 = 410.66 cm2

Area of design = Area of sector ACB - Area of equilateral ΔAOB

                       = 410.66 cm2 - 333.2 cm2 = 77.46 cm2

Area of 6 design = 6 × 77.46 cm2 = 464.76 cm2

Total cost of making design = 464.76 cm2 × ₹ 0.35 per cm2 = ₹ 162.66  

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