A round table cover has six equal designs as shown if tyhe radius of the cover is 28cm find the cost of making the designs at the rate of 0.35 per square cm
Answers
It can be observed that these designs are egments of the circle onslder segment APB. Chord AB Is a slde of e hexagon. Each chord will substitute 360/6 60° at the centre of the circle AOAB, AOB 60 OAB2OBA LAOB 180 L0AB:180 60°120 OAB 60 herefore, AOAB is an equilateral triangla rea of AOAB rea of sector OAPB rea of segment APB Area of sectcr OAPB rea of AOAB -$18 herefore are of designsa 464.8 cm2 ost of making 1 cm2 designs Rs 0.35 ost of making 464.76 cm2 designs 464.8 x 0.35 Rs 162.68 herefore, the cost of making such designs is s 162.68
Answer:
Step-by-step explanation:
Answer:
Good morning bro,
Step-by-step explanation:
Sum of all angles of triangle = 180°
∠A + ∠B + ∠O = 180°
⇒ 2 ∠A = 180° - 60°
⇒ ∠A = 120°/2
⇒ ∠A = 60°
Triangle is equilateral as ∠A = ∠B = ∠C = 60°
Area of equilateral ΔAOB = √3/4 × (OA)2 = √3/4 × 282 = 333.2 cm2
Area of sector ACB = (60°/360°) × π r2 cm2
= 1/6 × 22/7 × 28 × 28 = 410.66 cm2
Area of design = Area of sector ACB - Area of equilateral ΔAOB
= 410.66 cm2 - 333.2 cm2 = 77.46 cm2
Area of 6 design = 6 × 77.46 cm2 = 464.76 cm2
Total cost of making design = 464.76 cm2 × ₹ 0.35 per cm2 = ₹ 162.66
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