Question

a=route3-route2 and b=route3+route2 then find the value of a square+b square​

Answer 1

Step-by-step explanation:

Hi ,

( 3 + √2 ) / ( 3 - √2 ) = a + b√2

LHS = ( 3 + √2 ) / ( 3 - √2 )

= [ (3 + √2 )² ] / [ ( 3-√2 ) ( 3 + √2 ) ]

= [ 3² + 2×3×√2 + (√2)²] / ( 3² - ( √2 )²]

= ( 9 + 6√2 + 2 ) / ( 9 - 2 )

= ( 11 + 6√2 ) / 7

= ( 11/7 ) + ( 6/7 ) × √2

Now ,

LHS = RHS

( 11/7 ) + ( 6/7 ) ×√2 = a + b√2

Compare both sides, we get

a = 11/7 ;

b = 6/7 ;

I hope this helps you.

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