A row of 100 trees was asked to be cut such that all the trees at positions of multiples of 2 or 3 are cut and the rest are not cut. How many trees are left at the end?
Answers
Answer:
33 trees
Step-by-step explanation:
total trees to be cut = 100
Multiples of 2 or 3 (0-100) = 67
therefore, trees left = 100-67 = 33
Given; A row of 100 trees was asked to be cut such that all the trees at positions of multiples of 2 or 3 are cut and the rest are not cut.
To Find; Number of trees left at the end
Solution; It is given that A row of 100 trees was asked to be cut such that all the trees at positions of multiples of 2 or 3 are cut and the rest are not cut.
Total number of trees = 100
trees cut at positions 2 and 3. This means that the trees at multiples of 6 must be cut.
Trees that must be cut positions = 6, 12, 18,24 , 30 , 36 , 42 , 48 , 54 , 60 , 66 , 72, 78 , 84 , 90 , 96 = 16 positions
Number of trees left at end = 100 - 16 = 84
Hence the number of trees left at end are 84