Math, asked by sumedhavishnnoi887, 5 months ago

A row of 100 trees was asked to be cut such that all the trees at positions of multiples of 2 or 3 are cut and the rest are not cut. How many trees are left at the end?​

Answers

Answered by CuriousStudentSuh
9

Answer:

33 trees

Step-by-step explanation:

total trees to be cut = 100

Multiples of 2 or 3 (0-100) =  67

therefore, trees left = 100-67 = 33

Answered by halamadrid
0

Given; A row of 100 trees was asked to be cut such that all the trees at positions of multiples of 2 or 3 are cut and the rest are not cut.

To Find; Number of trees left at the end

Solution; It is given that A row of 100 trees was asked to be cut such that all the trees at positions of multiples of 2 or 3 are cut and the rest are not cut.

Total number of trees = 100

trees cut at positions 2 and 3. This means that the trees at multiples of 6 must be cut.

Trees that must be cut positions = 6, 12, 18,24 , 30 , 36 , 42 , 48 , 54 , 60 , 66 , 72, 78 , 84 , 90 , 96 = 16 positions

Number of trees left at end = 100 - 16 = 84

Hence the number of trees left at end are 84

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