Question

A Rs5/- coin thrown vertically upward rises to a height of 44.1 m. Calculate, the initial velocity of the coin and the

time taken by it to gain the maximum height. [g = 9.8 m/s2]​

Answer 1

Explanation:

Answer in the attachment

Answer 2

Answer:

Given, initial velocity, u=5ms

−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms

−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v

2

−u

2

=2as, we have

s=v

2

−u

2

/2a

=(0)

2

−(5)

2

/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s