Question

A RTC bus travels 200 km at uniform speed. If speed had been
10 km/h less, it would have taken 1 hour more for the same
journey. Write suitable quadratic equation for given data.​

Answer 1

Answer:

Step-by-step explanation:

Distance covered by the bus = 200

Let the speed of the bus be=xkm/hr

Then,

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Answer 2

The suitable quadratic equation for given data is $x^2-10x-2000=0$

Step-by-step explanation:

Since we have given that

Distance = 200 km

Let the speed be 'x'

new speed be 'x-1'

It takes 1 hour more for the same journey.

According to question, it becomes,

$\dfrac{200}{x-10}-\dfrac{200}{x}=1\\\\\dfrac{200(x-(x-10))}{x^2-10x}=1\\\\\dfrac{200(x-x+10)}{x^2-10x}=1\\\\2000=x^2-10x\\\\x^2-10x-2000=0\\\\x=50,x=-40$

Hence, the suitable quadratic equation for given data is $x^2-10x-2000=0$

# learn more:

A RTC bus travels 200 km at uniform speed. If speed had been

10 km/h less, it would have taken 1 hour more for the same

journey. Write suitable quadratic equation for given data

https://brainly.in/question/15431883