Physics, asked by raj0001, 1 year ago

A rubber ball falls on a floor from a height of 19.6m. Calculate the velocity which it strike the ground or what height will rhe hall rebounce if it looses 25% of energy to rebounce to ground

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Answered by ydharmendra888
37
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Answered by OOOIRKIOOO
33

Solution: - Here, h1 = 19.6m, v1 =?  

                  Loss of energy = 25%, h2 =?  

                  On striking the floor, Kinetic energy = Potential energy  

                  1/2mv12 = mgh1  

                    v1 = (2gh1) ^1/2 = (2*9.8 *19.6) ^1/2  

                    v1 = 19.6 m/s                                    

As the body loses 25% of its energy, final energy E2 = 75/100 of initial energy.  

                    Mgh2 = 75(mgh1)/100  

                   h2 = ¾ h1 = ¾ *19.6 = 14.7 m        

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