A rubber ball falls on a floor from a height of 19.6m. Calculate the velocity which it strike the ground or what height will rhe hall rebounce if it looses 25% of energy to rebounce to ground
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Solution: - Here, h1 = 19.6m, v1 =?
Loss of energy = 25%, h2 =?
On striking the floor, Kinetic energy = Potential energy
1/2mv12 = mgh1
v1 = (2gh1) ^1/2 = (2*9.8 *19.6) ^1/2
v1 = 19.6 m/s
As the body loses 25% of its energy, final energy E2 = 75/100 of initial energy.
Mgh2 = 75(mgh1)/100
h2 = ¾ h1 = ¾ *19.6 = 14.7 m
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