a rubber ball floats on water with its 1/3rd volume outside water. what is the density of rubber?
Answers
Answered by
54
Hey there!
Let 'g' be the acceleration due to gravity. 'p' be the density of water. So, p = 1 g/cm³ .
'V' be the volume of the Rubber and 'q' be the density of the Rubber.
Volume of Rubber within water = V – (1/3)V = (2/3)V = Volume of water displaced by the Rubber
Weight of the water displaced = (2/3)V × p × g
Weight of the Rubber = V × q × g
Since,
Rubber is floating on the surface,
(2/3)V × p × g = V × q × g
=> q = (2/3)p
That is, the density of the Rubber is (2/3) g/cm³
HOPE IT HELPS ^_^
#brainly star
#follow me
Let 'g' be the acceleration due to gravity. 'p' be the density of water. So, p = 1 g/cm³ .
'V' be the volume of the Rubber and 'q' be the density of the Rubber.
Volume of Rubber within water = V – (1/3)V = (2/3)V = Volume of water displaced by the Rubber
Weight of the water displaced = (2/3)V × p × g
Weight of the Rubber = V × q × g
Since,
Rubber is floating on the surface,
(2/3)V × p × g = V × q × g
=> q = (2/3)p
That is, the density of the Rubber is (2/3) g/cm³
HOPE IT HELPS ^_^
#brainly star
#follow me
sahilsarvade25:
it was really helpful
Similar questions