A rubber ball floats with one – third of its volume above the water. Calculate the relative density of the ball.
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Heya....
Here's your answer.....
Let 'g' be the acceleration due to gravity. 'p' be the density of water. So, p = 1 g/cm³ .
'V' be the volume of the Rubber and 'q' be the density of the Rubber.
Volume of Rubber within water = V – (1/3)V = (2/3)V = Volume of water displaced by the Rubber
Weight of the water displaced = (2/3)V × p × g
Weight of the Rubber = V × q × g
Since,
Rubber is floating on the surface,
(2/3)V × p × g = V × q × g
=> q = (2/3)p
That is, the density of the Rubber is (2/3) g/cm³
Thanks...!!!
XD
Sorry baby 'wink'
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