Physics, asked by SwapnilRao, 1 year ago

A rubber ball floats with one – third of its volume above the water. Calculate the relative density of the ball.

Answers

Answered by Anonymous
20

Heya....

Here's your answer.....


Let 'g' be the acceleration due to gravity. 'p' be the density of water. So, p = 1 g/cm³ .

'V' be the volume of the Rubber and 'q' be the density of the Rubber.


Volume of Rubber within water = V – (1/3)V = (2/3)V = Volume of water displaced by the Rubber


Weight of the water displaced = (2/3)V × p × g


Weight of the Rubber = V × q × g


Since,

Rubber is floating on the surface,


(2/3)V × p × g = V × q × g


=> q = (2/3)p


That is, the density of the Rubber is (2/3) g/cm³


Thanks...!!!

XD

Sorry baby 'wink'

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