Question

A rubber ball is dropped from 10 m height. If it gain 14 J energy at that height calculate its mass . [consider *G* is 10]
[Answer is 200gm]

Answer 1

Answer :

• Mass of the ball which is dropped from a height of 10 m, with a potential energy of 14 j under the influence of gravity of 10 m/s² is 0.14 kg.

Explanation :

Given :

• Height from which the ball is dropped, h = 10 m
• Acceleration due to gravity, g = 10 m/s²
• Potential energy of the ball, P.E. = 14 J

To find :

• Mass of the body, m = ?

Knowledge required :

By definition, Potential energy of the body is energy possessed by it due to it's state of rest or its the product of the mass, accelaration due to gravity and the height of the body.

So,

⠀⠀⠀⠀⠀⠀⠀⠀⠀P.E. = mgh

Where,

• P.E. = Potential energy possessed by the body.
• m = Mass of the body
• g = Acceleration due to gravity
• h = Height at which the body is kept

Solution :

By using the equation for potential energy (P.E.) and substituting the values in it, we get :

⠀⠀=> P.E. = mgh

⠀⠀=> 14 = m × 10 × 10

⠀⠀=> 14 = 100m

⠀⠀=> 14/100 = m

⠀⠀=> 0.14 = m

⠀⠀⠀⠀⠀⠀⠀⠀∴ m = 0.14 kg

Therefore,

• Mass of the body, m = 0.14 kg.

Answer 2

Explanation:

Given :

• A rubber ball is dropped from 10 m height. If it gain 14 J energy

• G = 10

To Find :

• calculate its mass

Solution :

Concept :

• The equation for gravitational potential energy is GPE = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 on Earth), and h is the height above the ground in meters.

________________________

We have

$: \implies \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \: mgh}$

Substitute all Values :

$: \implies \: \: \: \: \: \: \: \: \: \: \sf \: m \times 10 \times 10 \\ \\ \\ : \implies \: \: \: \: \: \: \: \: \: \: \sf \:100m$

Now

by exposed the protein in your diet

• first eat protein food then go to the weight lifter lift some weight then go to weight checker then observe potential energy after eat and after weight lifting.

$: \implies \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \:PE = mgh}$

Substitute all Values :

$: \implies \: \: \: \: \: \: \: \: \: \: \sf \:14 = 100m \\ \\ \\ : \implies \: \: \: \: \: \: \: \: \: \: \sf \:m = \cancel{ \frac{14}{100} } \\ \\ \\ : \implies \: \: \: \: \: \: \: \: \: \: \sf \:m = 0.14 kg$

$\therefore \: \: \underline{ \sf \: Hence \: the \: mass \: is \: 0.14 kg}$