Question

a rubber ball is dropped from the height of 100m,on striking the hard ground risesupby 40 m . What is the displacement od the ball?​

Answer 1

Answer:

Step-by-step explanation:

total distanc frm the top of the building is 100m

after striking it came up by 40m

then displacement = 100 - 40 = 60

therefore displacement is equal to 60m

Answer 2

Answer:

The magnitude of displacement of ball is 60m

Step-by-step explanation:

Given that,

A rubber ball is dropped from a height of 100m and on striking hard ground,it rises up by 40m.

We solve this problem using vectors.

When the ball is dropped from height of 100m,Displacement when it reaches ground is

$d _{1} = - 100j$

When the ball again rises up by 40m,Its displacement is

$d _{2} = + 40j$

Hence,the total displacement of ball is given as

$d = d _{1} + d _{2} = - 100j + 40j \\ = - 60j$

The magnitude of displacement is

$|d| = | - 60| = 60m$

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