Chemistry, asked by Kai0314, 1 day ago

A rubber ball is dropped into a concrete floor from a height of 2m. It rebounds to a height of 1.6m. How much is the fraction of energy did it loss in the process of striking the floor?

Answers

Answered by nareshkumarajariwal

0

Answer:

-3000 m/s²

Explanation:

h

1

=5m

h

2

=1.8

Velocity of ball just before hitting the ground =

2gh

1

=

10g

Velocity of ball just after hitting the ground =

2gh

2

=

3.6g

Loss in velocity=

10g

10g

−

3.6g

=1−

5

3

=

5

2

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