Question

a rubber ball of mass 0.05 kg falls from a height of 1m and rebounds to a height of 0.5 metre find the impulse​

Answer 1

Answer:

Given that,

Ball of mass = 5 0 g

Height = 1 m

Rebound to height = 0 . 5 m

Time = 0 . 1 s

Now,

Initial velocity of the ball =um/s

Let the final velocity =vm/s

b

Using equation of motion

v

2

=u

2

+2gh

v

2

=0+2×9 . 8×0 . 1

v=

1 . 9 6

v=1 . 4m/s

In the second time,

Final velocity=0m/s

Now, Using equation of motion

v

2

=u

2

-2gh

0=u

2

-2×9 . 8×0 . 5

u

2

=9 . 8

u=3 . 1m/s

Now, Impulse= change in linear momentum

=m v-m( - u )

=m( v+u )

=0 . 0 5×( 1 . 4+3 . 1 )

=0 . 2 2 5Ns

Now, the Force=Impulse/Time

F=

time

impulse

F=

0 . 1

0 . 2 2 5

F=2 . 2 5N

Hence, the impulse is 0 . 2 2 5 Ns and force is 2 . 2 5 N