A rubber ball of mass 1 kg hits the ground at anangle of 30 with ground and rebounds at angle of 60 with ground without change in speed. If the speed of ball is 1 m/s, then impulse imparted by ground to ball, is
Answers
Answer:
The impulse imparted by the ground to the ball is 1.414 kg.m/s
Given: Mass of rubber ball = 1 kg, Velocity of ball = 1 m/s
The ball hits at an angle of 30° with the ground and rebounds at an angle of 60° with the ground.
To Find: The impulse imparted by ground to ball
Solution:
- Impulse is defined as a term that is used to quantify the effect force required to change the momentum of an object.
- It is said that the ball hits at an angle of 30° with the ground and rebounds at an angle of 60° with the ground. So, we can see that the angle between the incident path and the reflected path is 90°.
- Now, since the normal divides the angle between the incident path and reflected path into two equal parts so,
Angle of incidence = Angle of reflection = 45°
Now the initial velocity of the ball along the normal = v cos Ф
= 1 cos 45°
and the final velocity of the ball along the normal = - v cos Ф
= - 1 cos 45°
Impulse imparted = m Δ v
= 1 × ( 1 cos 45° - ( - 1 cos 45° ))
= 2 cos 45°
= √2 kg.m/s
= 1.414 kg.m/s
Hence, the impulse imparted by the ground to the ball is 1.414 kg.m/s
#SPJ3