Question

a rubber ball of mass 25kg falls from a height of 2m and rebounds to a height of 1.5m find the impulse and the avg. force between the ball and the ground if time for which they are in contact is 0.1s

Answer 1

Explanation:

V² = u² + 2aS

Here , S = 2m , g = 10m/s²

∴ v² = 2 × 10 × 2 = 40 ⇒v = 2√10 m/s

v² = u² + 2as

Here, v = 0, a = - 10m/s² , s = 1.5m

∴u² = 2 × 10 × 1.5 = 30 ⇒u = √30 m/s

Impulse = mv -(-mu) = m(v+u)

= 0.025 × (2√10 + √30) kgm/s

=0.2948 Kgm/s

Answer 2

Attached above, hope you satisfied with my answer.

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