A rubber ball with mass .2 kg is dropped vertically from a height of 1.5 meters above a floor. The ball bounces off of the floor and during the bounce .60 J of energy os dissipated. What is the maximum height of the ball after the bounce
Answers
The ball will bounce back to a maximum height of 1.2 m
Explanation :
Net energy contained by the ball is the potential energy of the ball before drop,
PE = mgh = 0.2 x 10 x 1.5 = 3 J
after the drop 0.6 J of energy is dissipated, so energy remained
= 3 - 0.6 = 2.4 J
This energy is equivalent to new potential energy corresponding to new height. Hence,
mgh = 2.4
=> 0.2 x 10 x h = 2.4
=> h = 2.4/2 = 1.2
Hence the ball will bounce back to a maximum height of 1.2 m
Given A rubber ball with mass .2 kg is dropped vertically from a height of 1.5 meters above a floor. The ball bounces off of the floor and during the bounce .60 J of energy dissipated.
Potential energy is the energy acquired by a body by virtue of its position. So it is given by
P.E = mgh
= 0.2 x 9.8 x 1.5
P.E = 2.94 J
During bounce of ball 0.60 J of energy is lost. So
2.94 - 0.6 = 2.34 J
New P.E = mgh
2.34 = 0.2 x 9.8 x h
h = 2.34 / 0.2 x 9.8
V = 1.2 mtrs
The maximum height of the ball after the bounce is 1.2 mtrs