Question

A rubber balloon weighing 10g is 40cm in diameter when inflated with He(g) at 760torr and 270C.  Assuming density of air to be 1.2g/L under these conditions, the weight that the balloon can lift is (in grams)​

Answer 1

Answer:

28.8

Explanation:

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Answer 2

Answer:

The weight of balloon filled with $helium$ is equal to 15.45g.

The weight that the balloon can lift is 24.74g.

Explanation:

Given, radius of the balloon $r=20cm$

So, Volume of balloon,$V=\frac{4}{3}\pi r^{2}=\frac{4}{3}(3.14)(20)^{3}=33493.3cm^{3}=33493.3*10^{-3}dm^{3}$

Given, density of air, $=1.2gL^{-1}=1.2*10^{-3}gcm^{-3}$

Now, Mass displaced air $=(volume)(density)$

                              $=(33493.3)(1.2*10^{-3})=40.192g$

No. of moles of gas, $n=\frac{PV}{RT}=\frac{(1.013)(33493.3)(10^{-3})}{(0.083)(300)}=1.363moles$

Mass of $Helium$ $=(1.3623)(4)=5.450g$

Mass of $He$ filled Balloon $=10g+5.450=15.45g$

Payload = (mass displaced air)-(mass of filled balloon)

             $=40.192-15.45=24.74g$