Question

A rubber toy pops up to a maximum height of 2.51m. Find its initial velocity

Answer 1

Step-by-step explanation:

third equation of motion

v^=u^+2gh

v^=o

u=?

g= -10 because it go up

h=2.51

v^=u^+2gh

0=u^ +2* -10*2.51

0=u^-50.20

u^=50.20m/s